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(C) Using the formula: $\frac{M_1 D_1 H_1}{W_1} = \frac{M_2 D_2 H_2}{W_2}$Given:$M_1 = 105, D_1 = 25, H_1 = 8, W_1 = \frac{2}{5}$Let the additional me

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$35$

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(C) Using the formula: $\frac{M_1 D_1 H_1}{W_1} = \frac{M_2 D_2 H_2}{W_2}$Given:$M_1 = 105, D_1 = 25, H_1 = 8, W_1 = \frac{2}{5}$Let the additional men be $x$.Then,$M_2 = 105 + x, D_2 = 50 - 25 = 25, H_2 = 9, W_2 = 1 - \frac{2}{5} = \frac{3}{5}$Substituting the values into the formula:$\frac{105 	imes 25 	imes 8}{2/5} = \frac{(105 + x) 	imes 25 	imes 9}{3/5}$$\frac{105 	imes 25 	imes 8 	imes 5}{2} = \frac{(105 + x) 	imes 25 	imes 9 	imes 5}{3}$$105 	imes 4 = (105 + x) 	imes 3$$420 = 315 + 3x$$3x = 105$$x = 35$Therefore,$35$ additional men must be employed.

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