A container contains 32 ,g of O_2 at a temper | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The ideal gas equation is given by $PV = nRT$,where $n = \frac{m}{M}$ is the number of moles.For the first container: $m(O_2) = 32 \,g$,$M(O_2) =

Vedclass · Accepted Answer

$4P$

Vedclass · Answer

(B) The ideal gas equation is given by $PV = nRT$,where $n = \frac{m}{M}$ is the number of moles.For the first container: $m(O_2) = 32 \,g$,$M(O_2) = 32 \,g/mol$. Thus,$n_1 = \frac{32}{32} = 1 \,mol$.The pressure is $P = \frac{n_1 RT}{V} = \frac{1 \cdot RT}{V} = \frac{RT}{V}$.For the second container: $m(H_2) = 4 \,g$,$M(H_2) = 2 \,g/mol$. Thus,$n_2 = \frac{4}{2} = 2 \,mol$.The temperature is $2T$. The pressure $P'$ is given by $P' = \frac{n_2 R(2T)}{V} = \frac{2 \cdot R(2T)}{V} = \frac{4RT}{V}$.Substituting $\frac{RT}{V} = P$,we get $P' = 4P$.

$A$ container contains $32 \,g$ of $O_2$ at a temperature $T$. The pressure of the gas is $P$. An identical container containing $4 \,g$ of $H_2$ at a temperature $2T$ has a pressure of ............

Similar Questions

The $SI$ unit of universal gas constant is

When the pressure on $1200 \ ml$ of a gas is increased from $70 \ cm$ to $120 \ cm$ of mercury at constant temperature,the new volume of the gas will be ........ $ml$.

The tyre of a motor car contains air at $15^{\circ} C$. If the temperature increases to $35^{\circ} C$,the approximate percentage increase in pressure is (ignore the expansion of the tyre).

What is molar mass?

Write the ideal gas equation. What is the basis of the absolute temperature scale?

Vedclass Test Series

Exam Paper Generator

Online Exam Module