$A$ conductivity cell with two electrodes (shaded sides) is half-filled with an infinitely dilute aqueous solution of a weak electrolyte. If the volume is doubled by adding more water at a constant temperature,the molar conductivity of the cell will -

The conductivity of $0.001 \ M$ acetic acid at a certain temperature is $5.07 \times 10^{-5} \ S \ cm^{-1}$. If $\wedge_m^0$ of acetic acid at the same temperature is $390 \ S \ cm^2 \ mol^{-1}$,the dissociation constant of acetic acid at that temperature is:

The specific conductance of $0.0025 \ M$ acetic acid is $5 \times 10^{-5} \ S \ cm^{-1}$ at a certain temperature. The dissociation constant of acetic acid is $...... \times 10^{-7}$. (Nearest integer) Consider limiting molar conductivity of $CH_3COOH$ as $400 \ S \ cm^2 \ mol^{-1}$.

Which of the following solutions has the maximum conductivity?

$A$ conductivity cell has two electrodes $18 \ mm$ apart and having cross-sectional area $2.0 \ cm^2$. What is the value of the cell constant (in $cm^{-1}$)?

Resistance of a conductivity cell (cell constant $129 \; m^{-1}$) filled with $74.5 \; ppm$ solution of $KCl$ is $100 \; \Omega$ (labelled as solution $1$). When the same cell is filled with $KCl$ solution of $149 \; ppm$,the resistance is $50 \; \Omega$ (labelled as solution $2$). The ratio of molar conductivity of solution $1$ and solution $2$ is i.e.,$\frac{\wedge_{1}}{\wedge_{2}} = x \times 10^{-3}$. The value of $x$ is (Nearest integer). Given,molar mass of $KCl$ is $74.5 \; g \; mol^{-1}$.