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(C) The electric field $E$ at a distance $r$ from the center of a conducting sphere (where $r > R$) is given by the formula $E = \frac{kq}{r^2}$,where

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$ - 5.3 	imes 10^{-9} \, C$

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(C) The electric field $E$ at a distance $r$ from the center of a conducting sphere (where $r > R$) is given by the formula $E = \frac{kq}{r^2}$,where $k = \frac{1}{4 \pi \varepsilon_0} = 9 	imes 10^9 \, N \cdot m^2 \cdot C^{-2}$.Given: $r = 20 \, cm = 0.2 \, m$.The electric field points radially inwards,which implies the charge $q$ is negative. Thus,$E = -1.2 	imes 10^3 \, N \cdot C^{-1}$.Rearranging the formula for $q$: $q = \frac{E \cdot r^2}{k}$.Substituting the values: $q = \frac{(-1.2 	imes 10^3) 	imes (0.2)^2}{9 	imes 10^9}$.$q = \frac{-1.2 	imes 10^3 	imes 0.04}{9 	imes 10^9} = \frac{-0.048 	imes 10^3}{9 	imes 10^9} = -0.00533 	imes 10^{-6} \, C$.$q \approx -5.3 	imes 10^{-9} \, C$.

$A$ conducting sphere of radius $10 \, cm$ has an unknown charge. If the electric field at a distance $20 \, cm$ from the centre of the sphere is $1.2 \times 10^3 \, N \, C^{-1}$ and points radially inwards,the net charge on the sphere is:

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