A conducting circular loop of radius $r$ carries a constant current $i$. It is placed in uniform magnetic field $B$, such that $B$ is perpendicular to the plane of the loop. The net magnetic force acting on the loop is
$i r B$
$2 \pi r i B$
Zero
$\pi r i B$
Force on current carrying loop (Radius $= R$ ) in uniform magnetic $(B)$ field which is at an angle $30^{\circ}$ with the normal will be
A current carrying closed loop in the form of a right angle isosceles triangle $ABC$ is placed in a uniform magnetic field acting along $AB.$ If the magnetic force on the arm $BC$ is $\vec F,$ the force on the arm $AC$ is
A semicircular ring of radius $R$ carrying current $i$ is placed in a magnetic field of intensity $B$ so that plane of wire is perpendicular to magnetic field as shown. Net force acting on the ring is
A rigid square loop of side $a$ and carrying current $I_2$ is laying on a horizontal surface near a long current $I_1$ wire in the same plane as shown in figure. The net force on the loop due to the wire will be
Two thin, long, parallel wires, separated by a distance ‘$d$’ carry a current of ‘$i$’ in the same direction. They will