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Question

(A) The magnification $(m)$ produced by a spherical mirror is given by the formula:$m = -\frac{v}{u}$Since the image is real and magnified three times

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$-30$

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(A) The magnification $(m)$ produced by a spherical mirror is given by the formula:$m = -\frac{v}{u}$Since the image is real and magnified three times,the magnification $m = -3$ (as real images are inverted).Given,object distance $u = -10 \, cm$ (according to sign convention).Substituting the values in the formula:$-3 = -\frac{v}{-10}$$-3 = \frac{v}{10}$$v = -3 	imes 10 = -30 \, cm$.The negative sign indicates that the image is formed in front of the mirror at a distance of $30 \, cm$.

$A$ concave mirror produces a three times magnified (enlarged) real image of an object placed at $10 \, cm$ in front of it. Where is the image located (in $cm$)?

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