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(D) For a concave mirror,the focal length $f = -0.4\,m = -40\,cm$.For an upright (virtual) image,the magnification $m = +5$.The formula for magnificat

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$0.32$

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(D) For a concave mirror,the focal length $f = -0.4\,m = -40\,cm$.For an upright (virtual) image,the magnification $m = +5$.The formula for magnification in terms of focal length and object distance $u$ is $m = \frac{f}{f - u}$.Substituting the given values: $5 = \frac{-40}{-40 - u}$.Cross-multiplying: $5(-40 - u) = -40$.$-200 - 5u = -40$.$-5u = 160$.$u = -32\,cm$.Converting back to meters: $u = -0.32\,m$.The distance at which you hold the mirror is the magnitude of $u$,which is $0.32\,m$.

$A$ concave mirror for face viewing has a focal length of $0.4\,m$. The distance at which you hold the mirror from your face in order to see your image upright with a magnification of $5$ is......$m$.

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