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(C) The voltage gain $(A_v)$ of a common emitter amplifier is given by the product of the current gain $(\beta)$ and the resistance gain.First,calcula

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$990$

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(C) The voltage gain $(A_v)$ of a common emitter amplifier is given by the product of the current gain $(\beta)$ and the resistance gain.First,calculate the current gain $\beta$ using the relation $\beta = \frac{\alpha}{1 - \alpha}$:$\beta = \frac{0.99}{1 - 0.99} = \frac{0.99}{0.01} = 99$.Next,calculate the resistance gain,which is the ratio of the load resistance $(R_L)$ to the input impedance $(R_i)$:Resistance gain $= \frac{R_L}{R_i} = \frac{10 \ k\Omega}{1 \ k\Omega} = 10$.Finally,calculate the voltage gain:$A_v = \beta 	imes 	ext{Resistance gain} = 99 	imes 10 = 990$.

$A$ common emitter amplifier is designed with an $NPN$ transistor $(\alpha = 0.99)$. The input impedance is $1 \ k\Omega$ and the load resistance is $10 \ k\Omega$. The voltage gain will be:

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