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(C) The current gain $\beta$ for a common-emitter configuration is given by the formula $\beta = \frac{\alpha}{1 - \alpha}$.Given $\alpha = 0.99$, we

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$990$

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(C) The current gain $\beta$ for a common-emitter configuration is given by the formula $\beta = \frac{\alpha}{1 - \alpha}$.Given $\alpha = 0.99$, we calculate $\beta = \frac{0.99}{1 - 0.99} = \frac{0.99}{0.01} = 99$.The voltage gain $A_v$ of a common-emitter amplifier is given by $A_v = \beta 	imes \frac{R_{out}}{R_{in}}$.Substituting the given values: $A_v = 99 	imes \frac{10\, k\Omega}{1\, k\Omega} = 99 	imes 10 = 990$.Therefore, the voltage gain is $990$.

$A$ common-emitter amplifier is designed with a $n-p-n$ transistor $(\alpha = 0.99)$. The input impedance is $1\, k\Omega$ and load is $10\, k\Omega$. The voltage gain will be

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