$A$ coil of resistance $10 \, \Omega$ and an inductance $5 \, H$ is connected to a $100 \, V$ battery. The energy stored in the coil is:

If the current of $I$ gives rise to a magnetic flux $\phi$ through a coil having $N$ turns,then the magnetic energy stored in the medium surrounding the coil is

$A$ $50 \, mH$ coil carries a current of $2 \, A$. The energy stored in the coil in joules is:

$A$ coil has an inductance of $2 \, H$ and resistance of $4 \, \Omega$. $A$ $10 \, V$ potential difference is applied across the coil. The energy stored in the magnetic field after the current has built up to its equilibrium value will be $.......... \times 10^{-2} \, J$.

$A$ solenoid of inductance $2 \ H$ carries a current of $1 \ A$. What is the magnetic energy stored in the solenoid (in $J$)?

The energy stored in an inductor of self-inductance $L$ henry carrying a current of $I$ ampere is: