A closed tank has two compartments A and B,bo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Initial moles in compartment $A$ $(n_A)$: $n_A = \frac{P_A V_A}{R T_A} = \frac{5 	imes 1}{R 	imes 400} = \frac{1}{80R}$Initial moles in compartm

Vedclass · Accepted Answer

$2.22$

Vedclass · Answer

(A) Initial moles in compartment $A$ $(n_A)$: $n_A = \frac{P_A V_A}{R T_A} = \frac{5 	imes 1}{R 	imes 400} = \frac{1}{80R}$Initial moles in compartment $B$ $(n_B)$: $n_B = \frac{P_B V_B}{R T_B} = \frac{1 	imes 3}{R 	imes 300} = \frac{1}{100R}$Total moles $(n_{total})$ = $n_A + n_B = \frac{1}{80R} + \frac{1}{100R} = \frac{5+4}{400R} = \frac{9}{400R}$At equilibrium,the partition is conducting and movable,so both compartments will have the same pressure $(P)$ and temperature $(T)$.Let $V_A'$ and $V_B'$ be the new volumes. $V_A' + V_B' = 1 + 3 = 4 \ m^3$.Using the ideal gas law for the total system: $P(V_A' + V_B') = n_{total} R T$$P(4) = (\frac{9}{400R}) R T \implies P = \frac{9T}{1600}$For compartment $A$: $P V_A' = n_A R T \implies (\frac{9T}{1600}) V_A' = (\frac{1}{80R}) R T$$V_A' = \frac{1}{80} 	imes \frac{1600}{9} = \frac{20}{9} \approx 2.22 \ m^3$.

Similar Questions

The molecular weights of $O_2$ and $SO_2$ are $32$ and $64$ respectively. If $1 \, L$ of $O_2$ at $15 \, ^\circ C$ and $750 \, mm$ pressure contains '$N$' molecules,the number of molecules in $2 \, L$ of $SO_2$ under the same conditions of temperature and pressure will be

The pressure exerted by $6.0 \ g$ of methane gas in a $0.03 \ m^3$ vessel at $129^{\circ} C$ is $........ \ Pa$ (Atomic masses : $C = 12.01, H = 1.01$ and $R = 8.314 \ J K^{-1} mol^{-1}$)

$n$ moles of an ideal gas at temperature $T$ (in kelvin) occupy $V \ L$ of volume,exerting a pressure of $P$ atmospheres. What is the concentration (in $mol / L$)?

In an experiment during the analysis of a carbon compound,$145 \ L$ of $H_2$ was collected at $760 \ mm \ Hg$ pressure and $27 \ ^oC$ temperature. The mass of $H_2$ is nearly $....... \ g$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module