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(C) Let $M$,$P$,and $C$ represent the sets of students taking Mathematics,Physics,and Chemistry,respectively.Given:$n(M) = 100$$n(P) = 70$$n(C) = 40$$

Vedclass · Accepted Answer

$60$

Vedclass · Answer

(C) Let $M$,$P$,and $C$ represent the sets of students taking Mathematics,Physics,and Chemistry,respectively.Given:$n(M) = 100$$n(P) = 70$$n(C) = 40$$n(M \cap P) = 30$$n(M \cap C) = 28$$n(P \cap C) = 23$$n(M \cap P \cap C) = 18$To find the number of students who have offered Mathematics alone,we use the formula:$n(M 	ext{ only}) = n(M) - [n(M \cap P) + n(M \cap C) - n(M \cap P \cap C)]$$n(M 	ext{ only}) = 100 - [30 + 28 - 18]$$n(M 	ext{ only}) = 100 - [40]$$n(M 	ext{ only}) = 60$Thus,$60$ students have offered Mathematics alone.

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