A circus tent is cylindrical to a height of 3 | vedclass

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(C) The radius of the base of the tent is $r = 105/2 = 52.5\, m$.The curved surface area of the cylindrical part is given by $2\pi rh = 2 	imes (22/7

Vedclass · Accepted Answer

$1947$

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(C) The radius of the base of the tent is $r = 105/2 = 52.5\, m$.The curved surface area of the cylindrical part is given by $2\pi rh = 2 	imes (22/7) 	imes 52.5 	imes 3 = 990\, m^2$.The lateral surface area of the conical part is given by $\pi rl = (22/7) 	imes 52.5 	imes 53 = 8745\, m^2$.The total surface area of the canvas required is the sum of these two areas: $990 + 8745 = 9735\, m^2$.Given the width of the canvas is $5\, m$,the length of the canvas is calculated as: $	ext{Length} = 	ext{Total Area} / 	ext{Width} = 9735 / 5 = 1947\, m$.

$A$ circus tent is cylindrical to a height of $3\, m$ and conical above it. If its diameter is $105\, m$ and the slant height of the conical portion is $53\, m$,calculate the length of the canvas $5\, m$ wide required to make the tent. (in $m$)

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