A circular coil of radius 4, cm and of 20 tur | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The magnetic dipole moment $M$ of a coil is given by the formula $M = N \cdot i \cdot A$,where $N$ is the number of turns,$i$ is the current,and $

Vedclass · Accepted Answer

$0.3$

Vedclass · Answer

(B) The magnetic dipole moment $M$ of a coil is given by the formula $M = N \cdot i \cdot A$,where $N$ is the number of turns,$i$ is the current,and $A$ is the area of the coil.Given:$N = 20$$i = 3\, A$$r = 4\, cm = 4 	imes 10^{-2}\, m$Area $A = \pi r^2 = \pi 	imes (4 	imes 10^{-2})^2 = 16\pi 	imes 10^{-4}\, m^2$.Using $\pi \approx 3.14$:$A \approx 3.14 	imes 16 	imes 10^{-4} = 50.24 	imes 10^{-4}\, m^2$.Now,$M = 20 	imes 3 	imes 50.24 	imes 10^{-4} = 60 	imes 50.24 	imes 10^{-4} = 3014.4 	imes 10^{-4} \approx 0.3\, A \cdot m^2$.Thus,the correct option is $B$.

$A$ circular coil of radius $4\, cm$ and of $20$ turns carries a current of $3$ amperes. It is placed in a magnetic field of intensity $0.5\, Wb/m^2$. The magnetic dipole moment of the coil is.......$A \cdot m^2$.

Similar Questions

The magnitude of magnetic induction at a point on the axis at a large distance $(r)$ from the centre of a circular coil of $n$ turns and area $A$ carrying current $I$ is given by:

Due to the flow of current in a circular loop of radius $R$,the magnetic field produced at the centre of the loop is $B$. The magnetic moment of the loop is:

Magnetic induction produced at the centre of a circular loop of radius $R$ carrying a current is $B$. The magnetic moment of the loop is $(\mu_0 = \text{permeability of free space})$

An $\alpha$ particle is revolving in a circle of radius $r$ with frequency $f$. Find the value of its magnetic dipole moment.

$A$ circular loop has a radius of $5\, cm$ and it is carrying a current of $0.1\, A$. Its magnetic moment is

Vedclass Test Series

Exam Paper Generator

Online Exam Module