A circuit connected to an ac source of emf e | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The phase difference $\phi$ in an $RL$ or $RC$ circuit is given by $	an \phi = \frac{X}{R}$.Given $\phi = \frac{\pi}{4}$,we have $	an(\frac{\pi}

Vedclass · Accepted Answer

$RC$ circuit with $R = 1 	ext{ k}\Omega$ and $C = 1 \mu	ext{F}$

Vedclass · Answer

(A) The phase difference $\phi$ in an $RL$ or $RC$ circuit is given by $	an \phi = \frac{X}{R}$.Given $\phi = \frac{\pi}{4}$,we have $	an(\frac{\pi}{4}) = 1$,which implies $X = R$.Here,$\omega = 1000 	ext{ rad/s}$ and $R = 1000 \Omega$.For an $RC$ circuit,$X_C = \frac{1}{\omega C} = R \implies C = \frac{1}{\omega R} = \frac{1}{1000 	imes 1000} = 10^{-6} 	ext{ F} = 1 \mu	ext{F}$.For an $RL$ circuit,$X_L = \omega L = R \implies L = \frac{R}{\omega} = \frac{1000}{1000} = 1 	ext{ H}$.Checking the options:Option $(A)$: $R = 1000 \Omega$,$C = 1 \mu	ext{F}$. $X_C = \frac{1}{1000 	imes 10^{-6}} = 1000 \Omega$. Since $X_C = R$,the phase difference is $\frac{\pi}{4}$.Thus,option $(A)$ is correct.

$A$ circuit connected to an $ac$ source of $emf$ $e = e_0 \sin(1000t)$,where $t$ is in seconds,exhibits a phase difference of $\frac{\pi}{4}$ between the $emf$ $e$ and current $i$. Which of the following circuits will exhibit this?

Similar Questions

$A$ capacitor of reactance $4 \sqrt{3} \Omega$ and a resistor of resistance $4 \Omega$ are connected in series with an $AC$ source of peak value $8 \sqrt{2} \text{ V}$. The power dissipation in the circuit is . . . . . $\text{W}$.

When $100 \ V$ $d.c.$ is applied across a solenoid,a current of $1 \ A$ flows in it. When $100 \ V$ $a.c.$ is applied across it,the current drops to $0.5 \ A$. If the frequency is $50 \ Hz$,the impedance and inductance are:

An electric bulb has a rated power of $50 \, W$ at $100 \, V$. If it is used on an $AC$ source of $200 \, V, 50 \, Hz$, a choke has to be used in series with it. This choke should have an inductance of (in $ \, H$)

When a coil is connected across a $20 \ V$ $DC$ supply,it draws a current of $5 \ A$. When it is connected across a $20 \ V, 50 \ Hz$ $AC$ supply,it draws a current of $4 \ A$. The self-inductance of the coil is .............. $mH$. (Take $\pi=3$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module