$A$ charged particle of charge $q$ and mass $m$ is accelerated through a potential difference of $V$ volts. It enters a region of orthogonal magnetic field $B$. The radius of its circular path will be:

  • A
    $\sqrt{\frac{2mV}{qB^2}}$
  • B
    $\frac{2mV}{qB^2}$
  • C
    $\frac{1}{B} \sqrt{\frac{2mV}{q}}$
  • D
    $\frac{1}{B} \sqrt{\frac{mV}{q}}$

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