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(B) Let the two-digit number be represented as $10x + y$,where $x$ is the tens digit and $y$ is the units digit.According to the first condition,the n

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$27$

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(B) Let the two-digit number be represented as $10x + y$,where $x$ is the tens digit and $y$ is the units digit.According to the first condition,the number is three times the sum of its digits:$10x + y = 3(x + y)$$10x + y = 3x + 3y$$7x = 2y$$\frac{x}{y} = \frac{2}{7}$This implies $x = 2$ and $y = 7$ (since $x$ and $y$ are single digits).Thus,the number is $27$.Verification with the second condition:If $45$ is added to the number $27$:$27 + 45 = 72$Here,the digits $2$ and $7$ are reversed to become $72$.Therefore,the number is $27$.

$A$ certain two-digit number is three times the sum of its digits. If $45$ is added to the number,the digits are reversed. Find the number.

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