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(A) Molecular formula $= X_4O_6$.Mass of compound $= 10 \ g$.Mass of $X = 5.72 \ g$.Mass of $O = 10 - 5.72 = 4.28 \ g$.Number of moles of $X$ $(n_X)$

Vedclass · Accepted Answer

$32$

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(A) Molecular formula $= X_4O_6$.Mass of compound $= 10 \ g$.Mass of $X = 5.72 \ g$.Mass of $O = 10 - 5.72 = 4.28 \ g$.Number of moles of $X$ $(n_X)$ $= \frac{5.72}{Mw_X}$ and number of moles of $O$ $(n_O)$ $= \frac{4.28}{16}$.From the formula $X_4O_6$,the ratio of moles is $\frac{n_X}{n_O} = \frac{4}{6}$.$\frac{5.72 / Mw_X}{4.28 / 16} = \frac{4}{6}$.$Mw_X = \frac{5.72 	imes 16 	imes 6}{4.28 	imes 4} = \frac{549.12}{17.12} \approx 32.07 \ g/mol$.Thus,the atomic mass of $X$ is approximately $32 \ amu$.

$A$ certain compound has the molecular formula $X_4O_6$. If $10 \ g$ of $X_4O_6$ has $5.72 \ g$ of $X$,the atomic mass of $X$ is ............ $amu$.

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