(A) Given:$emf (E) = 4\,V$Internal resistance $(r) = 0.5\,\Omega$External resistance $(R) = 7.5\,\Omega$First,calculate the current $(I)$ flowing thro

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(A) Given:$emf (E) = 4\,V$Internal resistance $(r) = 0.5\,\Omega$External resistance $(R) = 7.5\,\Omega$First,calculate the current $(I)$ flowing through the circuit using Ohm's law:$I = \frac{E}{R + r} = \frac{4}{7.5 + 0.5} = \frac{4}{8} = 0.5\,A$The terminal potential difference $(V)$ is given by the formula:$V = E - Ir$$V = 4 - (0.5 \times 0.5)$$V = 4 - 0.25$$V = 3.75\,V$Alternatively,$V = IR = 0.5 \times 7.5 = 3.75\,V$.

Class 12 Physics Current Electricity Electric Cells and Combination of cells in Series and Parallel

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$A$ cell of $emf\;4\,V$ and internal resistance $0.5\,\Omega$ is connected to a $7.5\,\Omega$ external resistance. The terminal potential difference of the cell is $.....\,V$.

NEET 2022 All NEET

A
$3.75$
B
$4.25$
C
$4$
D
$0.375$

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Current Electricity

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Electric Cells and Combination of cells in Series and Parallel

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$A$ cell of $emf\;4\,V$ and internal resistance $0.5\,\Omega$ is connected to a $7.5\,\Omega$ external resistance. The terminal potential difference of the cell is $.....\,V$.

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