$A$ carboxylic acid (molecular formula $C_{2}H_{4}O_{2}$) reacts with an alcohol in the presence of an acid catalyst to form a compound $'X'$. The alcohol on oxidation with alkaline $KMnO_{4}$ followed by acidification gives the same carboxylic acid $C_{2}H_{4}O_{2}$. Write the name and structure of $(i)$ carboxylic acid,$(ii)$ alcohol,and $(iii)$ the compound $'X'$.

(N/A) $(i)$ Carboxylic acid: Ethanoic acid $(CH_{3}COOH)$. Structure: $CH_{3}-C(=O)OH$.
$(ii)$ Alcohol: Ethanol $(CH_{3}CH_{2}OH)$. Structure: $CH_{3}-CH_{2}-OH$.
$(iii)$ Compound $'X'$: Ethyl ethanoate $(CH_{3}COOC_{2}H_{5})$. Structure: $CH_{3}-C(=O)-O-CH_{2}-CH_{3}$.
Explanation: The reaction between ethanoic acid and ethanol in the presence of an acid catalyst is an esterification reaction,producing the ester ethyl ethanoate $('X')$.