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(C) Let the total distance be $2d$. The car travels the first half distance $d$ with velocity $v_1 = 40 \, km/h$ and the second half distance $d$ with

Vedclass · Accepted Answer

$48$

Vedclass · Answer

(C) Let the total distance be $2d$. The car travels the first half distance $d$ with velocity $v_1 = 40 \, km/h$ and the second half distance $d$ with velocity $v_2 = 60 \, km/h$.Time taken for the first half is $t_1 = \frac{d}{v_1} = \frac{d}{40}$.Time taken for the second half is $t_2 = \frac{d}{v_2} = \frac{d}{60}$.Average velocity $v_{av} = \frac{	ext{Total distance}}{	ext{Total time}} = \frac{2d}{t_1 + t_2} = \frac{2d}{\frac{d}{40} + \frac{d}{60}}$.$v_{av} = \frac{2}{\frac{1}{40} + \frac{1}{60}} = \frac{2}{\frac{3+2}{120}} = \frac{2 	imes 120}{5} = \frac{240}{5} = 48 \, km/h$.

$A$ car travels half the distance with a constant velocity of $40 \, km/h$ and the remaining half with a constant velocity of $60 \, km/h$. The average velocity of the car in $km/h$ is

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