A car has a fresh battery of e.m.f. 12, V and | vedclass

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(D) The terminal voltage $V$ of a battery is given by the formula $V = E - I \cdot r$,where $E$ is the electromotive force $(e.m.f.)$,$I$ is the curre

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$7.5$

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(D) The terminal voltage $V$ of a battery is given by the formula $V = E - I \cdot r$,where $E$ is the electromotive force $(e.m.f.)$,$I$ is the current drawn,and $r$ is the internal resistance.Given:$E = 12\, V$$I = 90\, A$$r = 0.05\, \Omega$Substituting these values into the formula:$V = 12 - (90 	imes 0.05)$$V = 12 - 4.5$$V = 7.5\, V$Therefore,the terminal voltage when the starter is on is $7.5\, V$.

$A$ car has a fresh battery of $e.m.f.$ $12\, V$ and internal resistance of $0.05\, \Omega$. If the starter motor draws a current of $90\, A$,the terminal voltage when the starter is on will be ............... $V$.

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