(D) The formula for the capillary rise is given by $h = \frac{2T \cos \theta}{rdg}$.Here,$h = 5\,cm$,$r = 0.2\,cm$,$\theta = 60^o$,$d = 1\,gm/cm^3$,an

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(D) The formula for the capillary rise is given by $h = \frac{2T \cos \theta}{rdg}$.Here,$h = 5\,cm$,$r = 0.2\,cm$,$\theta = 60^o$,$d = 1\,gm/cm^3$,and $g = 980\,cm/s^2$.Rearranging the formula for surface tension $T$,we get $T = \frac{hrdg}{2 \cos \theta}$.Substituting the values: $T = \frac{5 \times 0.2 \times 1 \times 980}{2 \times \cos 60^o}$.Since $\cos 60^o = 0.5$,we have $T = \frac{5 \times 0.2 \times 980}{2 \times 0.5}$.$T = \frac{1 \times 980}{1} = 980\,dynes/cm$.

Class 11 Physics Fluid Mechanics and Surface Tension Capillary Tube and Capillarity

Medium

$A$ capillary tube of radius $0.2\,cm$ is dipped vertically in a beaker containing liquid. If the liquid rises to a height of $5\,cm$ for which the angle of contact is $60^o$,then the surface tension of the liquid is ...... $dynes/cm$ (given density $d = 1\,gm/cm^3$ and acceleration due to gravity $g = 980\,cm/s^2$).

A
$49$
B
$98$
C
$490$
D
$980$

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Class 11 Questions

Class 11

Physics Questions

Chapter

Fluid Mechanics and Surface Tension

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Capillary Tube and Capillarity

When two capillary tubes of different diameters are dipped vertically,the rise of the liquid is

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Two capillary tubes of same diameter are put vertically one each in two liquids whose relative densities are $0.8$ and $0.6$ and surface tensions are $60$ and $50 \text{ dyne/cm}$ respectively. The ratio of the heights of the liquids in the two tubes $\frac{h_1}{h_2}$ is:

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$A$ $20 \ cm$ long capillary tube is dipped in water. The water rises up to $8 \ cm$. If the entire arrangement is put in a freely falling elevator,the length of the water column in the capillary will be ....... $cm$.

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Water rises in a capillary tube of radius $r$ up to a height $h$. The mass of water in the capillary is $m$. The mass of water that will rise in a capillary tube of radius $\frac{r}{3}$ will be:

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Two capillary tubes $P$ and $Q$ are dipped vertically in water. The height of water level in capillary tube $P$ is $\frac{2}{3}$ of the height in capillary tube $Q$. The ratio of their diameters is

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When two capillary tubes of different diameters are dipped vertically,the rise of the liquid is

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