(C) Work done by $A$ in $3$ days $= 3 \times \frac{1}{12} = \frac{1}{4}$.Remaining work $= 1 - \frac{1}{4} = \frac{3}{4}$.Now,the combined $1$ day's w

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(C) Work done by $A$ in $3$ days $= 3 \times \frac{1}{12} = \frac{1}{4}$.Remaining work $= 1 - \frac{1}{4} = \frac{3}{4}$.Now,the combined $1$ day's work of $(A + B) = \frac{1}{12} + \frac{1}{15} = \frac{5 + 4}{60} = \frac{9}{60} = \frac{3}{20}$.Time taken to finish the remaining work $= \frac{\text{Remaining work}}{\text{Combined work rate}} = \frac{3/4}{3/20} = \frac{3}{4} \times \frac{20}{3} = 5$ days.

Competitive Quantitative Aptitude Time and Work and Wages Time and Work

Medium

$A$ can finish a work in $12$ days and $B$ can do it in $15$ days. After $A$ had worked for $3$ days,$B$ also joined $A$ to finish the remaining work. In how many days will the remaining work be finished?

A
$5\frac{1}{2}$
B
$4\frac{1}{2}$
C
$5$
D
$6$

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Quantitative Aptitude Questions

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Time and Work and Wages

Subtopic

Time and Work

$A$ and $B$ working separately can do a piece of work in $9$ and $12$ days,respectively. If they work for a day alternately with $A$ beginning,the work would be completed in (in days):

Medium

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Nikita,Nishita,and Kavita can complete a work in $2 \frac{2}{3}$ days. If Nishita and Kavita can complete it in $4$ days,and Nishita alone can do it in $6$ days,then in how many days can Nikita and Nishita complete the work?

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If $6$ men and $8$ boys can do a piece of work in $10$ days and $26$ men and $48$ boys can do the same work in $2$ days,the time taken by $15$ men and $20$ boys to do the same type of work will be (in days)

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$40$ men can complete a work in $40$ days. They started the work together. But at the end of each $10^{th}$ day,$5$ men left the job. The work would have been completed in (in days):

Medium

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$A$ certain sum of money is sufficient to pay wages for $21$ days of $X$ or $28$ days of $Y$. The money is sufficient to pay the wages of both for ........ days.

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$A$ can finish a work in $12$ days and $B$ can do it in $15$ days. After $A$ had worked for $3$ days,$B$ also joined $A$ to finish the remaining work. In how many days will the remaining work be finished?

Similar Questions

$A$ and $B$ working separately can do a piece of work in $9$ and $12$ days,respectively. If they work for a day alternately with $A$ beginning,the work would be completed in (in days):

Nikita,Nishita,and Kavita can complete a work in $2 \frac{2}{3}$ days. If Nishita and Kavita can complete it in $4$ days,and Nishita alone can do it in $6$ days,then in how many days can Nikita and Nishita complete the work?

If $6$ men and $8$ boys can do a piece of work in $10$ days and $26$ men and $48$ boys can do the same work in $2$ days,the time taken by $15$ men and $20$ boys to do the same type of work will be (in days)

$40$ men can complete a work in $40$ days. They started the work together. But at the end of each $10^{th}$ day,$5$ men left the job. The work would have been completed in (in days):

$A$ certain sum of money is sufficient to pay wages for $21$ days of $X$ or $28$ days of $Y$. The money is sufficient to pay the wages of both for ........ days.

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