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(A) Let the total distance be $3x$. The distance for each segment is $x$.The time taken for the first segment is $t_1 = \frac{x}{10}$.The time taken f

Vedclass · Accepted Answer

$18$

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(A) Let the total distance be $3x$. The distance for each segment is $x$.The time taken for the first segment is $t_1 = \frac{x}{10}$.The time taken for the second segment is $t_2 = \frac{x}{20}$.The time taken for the third segment is $t_3 = \frac{x}{60}$.The average speed $v_{avg}$ is given by the total distance divided by the total time:$v_{avg} = \frac{3x}{t_1 + t_2 + t_3} = \frac{3x}{\frac{x}{10} + \frac{x}{20} + \frac{x}{60}}$.Factoring out $x$:$v_{avg} = \frac{3}{\frac{1}{10} + \frac{1}{20} + \frac{1}{60}} = \frac{3}{\frac{6+3+1}{60}} = \frac{3}{\frac{10}{60}} = \frac{3 	imes 60}{10} = 18\; km/h$.

$A$ bus travels the first one-third distance at a speed of $10\; km/h$,the next one-third at $20\; km/h$,and the last one-third at $60\; km/h$. The average speed of the bus is ........ $km/h$.

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