A bus decreases its speed from 80 , km , h^{- | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Initial velocity $u = 80 \, km \, h^{-1} = 80 	imes \frac{5}{18} = \frac{200}{9} \, m \, s^{-1} \approx 22.22 \, m \, s^{-1}$.Final velocity $v =

Vedclass · Accepted Answer

$-2.083 \, m \, s^{-2}$

Vedclass · Answer

(B) Initial velocity $u = 80 \, km \, h^{-1} = 80 	imes \frac{5}{18} = \frac{200}{9} \, m \, s^{-1} \approx 22.22 \, m \, s^{-1}$.Final velocity $v = 50 \, km \, h^{-1} = 50 	imes \frac{5}{18} = \frac{125}{9} \, m \, s^{-1} \approx 13.89 \, m \, s^{-1}$.Time $t = 4 \, s$.Using the formula for acceleration $a = \frac{v - u}{t}$:$a = \frac{\frac{125}{9} - \frac{200}{9}}{4} = \frac{-75}{9 	imes 4} = \frac{-75}{36} = -2.083 \, m \, s^{-2}$.The negative sign indicates retardation or deceleration.

$A$ bus decreases its speed from $80 \, km \, h^{-1}$ to $50 \, km \, h^{-1}$ in $4 \, s$. Find the acceleration of the bus.

Similar Questions

When is an object in motion considered to be a point object?

$A$ cyclist driving at $5\, m s^{-1}$ picks up a velocity of $10\, m s^{-1}$ over a distance of $50\, m$. Calculate $(i)$ acceleration $(ii)$ time in which the cyclist picks up the above velocity.

Answer the following questions:
$(i)$ State the type of motion shown by a freely falling stone.
$(ii)$ When a stone is thrown vertically upwards,its velocity is continuously decreased. Why?
$(iii)$ Give an example of a motion in which average velocity is zero,but the average speed is not zero.

What conclusion can you draw from the displacement$-$time graph of a body shown below?

Can the distance travelled by a particle be zero when displacement is not zero?

Vedclass Test Series

Exam Paper Generator

Online Exam Module