A boy can throw a stone up to a maximum heigh | vedclass

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Question

$\begin{array}{l}
R = \frac{{{u^2}{{\sin }^2}	heta }}{g},H = \frac{{{u^2}{{\sin }^2}	heta }}{{2g}};{H_{\max }}at2	heta  = 90\
{H_{\max }} =

Vedclass · Accepted Answer

$20$

Vedclass · Answer

$\begin{array}{l}
R = \frac{{{u^2}{{\sin }^2}	heta }}{g},H = \frac{{{u^2}{{\sin }^2}	heta }}{{2g}};{H_{\max }}at2	heta  = 90\
{H_{\max }} = \frac{{{u^2}}}{{2g}}\,; = 10 \Rightarrow {u^2} = 10g 	imes 2\
R = \frac{{{u^2}\sin 2	heta }}{{\left( g ight)}} \Rightarrow {R_{\max }} = \frac{{{u^2}}}{g}\
{R_{\max }} = \frac{{10 	imes g 	imes 2}}{g} = 20\,meter
\end{array}$

A boy can throw a stone up to a maximum height of $10\ m$. The maximum horizontal distance that the boy can throw the same stone up to will be .......... $m$

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