A body with mass 2, kg moves in one direction | vedclass

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(C) From the given potential energy graph:At $x = 2\, m$,the potential energy $U_i = 6\, J$.At $x = 5\, m$,the potential energy $U_f = 2\, J$.Since th

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$2$

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(C) From the given potential energy graph:At $x = 2\, m$,the potential energy $U_i = 6\, J$.At $x = 5\, m$,the potential energy $U_f = 2\, J$.Since the body is released from rest at $x = 2\, m$,its initial kinetic energy $K_i = 0$.According to the law of conservation of mechanical energy,the total mechanical energy remains constant:$K_i + U_i = K_f + U_f$$0 + 6 = K_f + 2$$K_f = 6 - 2 = 4\, J$Since $K_f = \frac{1}{2} m v^2$,where $m = 2\, kg$:$4 = \frac{1}{2} 	imes 2 	imes v^2$$4 = v^2$$v = 2\, m/s$.

$A$ body with mass $2\, kg$ moves in one direction in the presence of a force which is described by the potential energy graph. If the body is released from rest at $x = 2\, m$,then its speed when it crosses $x = 5\, m$ is ................ $m/s$.

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