A body of mass 0.01 kg executes simple harmo | vedclass

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(D) From the given force-displacement graph,the force $F$ is related to displacement $x$ by $F = -kx$.Taking the magnitude,the slope of the graph give

Vedclass · Accepted Answer

$0.31$

Vedclass · Answer

(D) From the given force-displacement graph,the force $F$ is related to displacement $x$ by $F = -kx$.Taking the magnitude,the slope of the graph gives the force constant $k$:$k = |\frac{F}{x}| = \frac{8.0 \ N}{2.0 \ m} = 4.0 \ N/m$.The mass of the body is $m = 0.01 \ kg$.The time period $T$ of simple harmonic motion is given by the formula:$T = 2\pi \sqrt{\frac{m}{k}}$Substituting the values:$T = 2 	imes 3.14159 	imes \sqrt{\frac{0.01}{4.0}}$$T = 2 	imes 3.14159 	imes \sqrt{0.0025}$$T = 2 	imes 3.14159 	imes 0.05$$T = 0.314 \ s \approx 0.31 \ s$.

$A$ body of mass $0.01 \ kg$ executes simple harmonic motion $(S.H.M.)$ about $x = 0$ under the influence of a force shown in the graph. The period of the $S.H.M.$ is .... $s$

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