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(C) The net force $\vec{F}_{net}$ acting on the body is the vector sum of the two forces:$\vec{F}_{net} = \vec{F}_1 + \vec{F}_2 = (5 \hat{i} + 8 \hat{

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$2 \hat{i} + \hat{j} + \hat{k}$

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(C) The net force $\vec{F}_{net}$ acting on the body is the vector sum of the two forces:$\vec{F}_{net} = \vec{F}_1 + \vec{F}_2 = (5 \hat{i} + 8 \hat{j} + 7 \hat{k}) + (3 \hat{i} - 4 \hat{j} - 3 \hat{k})$$\vec{F}_{net} = (5+3) \hat{i} + (8-4) \hat{j} + (7-3) \hat{k} = 8 \hat{i} + 4 \hat{j} + 4 \hat{k} \ N$.According to Newton's second law,$\vec{F} = m \vec{a}$,so the acceleration $\vec{a} = \frac{\vec{F}_{net}}{m}$.Given mass $m = 4 \ kg$,we have:$\vec{a} = \frac{8 \hat{i} + 4 \hat{j} + 4 \hat{k}}{4} = 2 \hat{i} + \hat{j} + \hat{k} \ m/s^2$.

$A$ body of mass $4 \ kg$ experiences two forces $\overrightarrow{F}_1 = 5 \hat{i} + 8 \hat{j} + 7 \hat{k}$ and $\overrightarrow{F}_2 = 3 \hat{i} - 4 \hat{j} - 3 \hat{k}$. The acceleration acting on the body is :

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