A body of mass 500 , g is at rest on a fricti | vedclass

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(B) Given: Mass $m = 500 \, g = 0.5 \, kg$,Time $t = 10 \, s$,Force $F = 10^{-2} \, N = 0.01 \, N$,and Initial velocity $u = 0 \, m/s$.First,calculate

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$1$

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(B) Given: Mass $m = 500 \, g = 0.5 \, kg$,Time $t = 10 \, s$,Force $F = 10^{-2} \, N = 0.01 \, N$,and Initial velocity $u = 0 \, m/s$.First,calculate the acceleration $a$ using Newton's second law of motion,$F = ma$:$a = \frac{F}{m} = \frac{0.01 \, N}{0.5 \, kg} = 0.02 \, m/s^2$.Next,use the second equation of motion to calculate the distance $S$ travelled:$S = ut + \frac{1}{2}at^2$$S = 0 	imes 10 + \frac{1}{2} 	imes 0.02 	imes (10)^2$$S = 0 + 0.01 	imes 100 = 1 \, m$.Therefore,the distance travelled by the body is $1 \, m$.

$A$ body of mass $500 \, g$ is at rest on a frictionless surface. Calculate the distance travelled by it in $10 \, s$ when acted upon by a force of $10^{-2} \, N$. (in $, m$)

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