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Question

(A) The body starts from rest $(u = 0)$ and is accelerated uniformly to a speed $v$ in time $T$.The acceleration $a$ is given by $a = \frac{v - u}{T}

Vedclass · Accepted Answer

$\frac{m v^2 t}{T^2}$

Vedclass · Answer

(A) The body starts from rest $(u = 0)$ and is accelerated uniformly to a speed $v$ in time $T$.The acceleration $a$ is given by $a = \frac{v - u}{T} = \frac{v}{T}$.The velocity at any time $t$ is $v(t) = at = \frac{v}{T} t$.The force acting on the body is $F = ma = m \left( \frac{v}{T} \right)$.Instantaneous power $P$ is defined as $P = F \cdot v(t)$.Substituting the expressions for $F$ and $v(t)$:$P = \left( m \frac{v}{T} \right) \left( \frac{v}{T} t \right)$.Simplifying the expression:$P = \frac{m v^2 t}{T^2}$.

$A$ body of mass $m$ is accelerated uniformly from rest to a speed $v$ in a time $T$. The instantaneous power delivered to the body as a function of time is given by

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