(C) For a body projected horizontally from a height $h$,the time taken to reach the ground is given by $t = \sqrt{\frac{2h}{g}}$.Given $h = 5 \, m$ an

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(C) For a body projected horizontally from a height $h$,the time taken to reach the ground is given by $t = \sqrt{\frac{2h}{g}}$.Given $h = 5 \, m$ and $g = 10 \, m/s^2$,we have $t = \sqrt{\frac{2 \times 5}{10}} = \sqrt{1} = 1 \, s$.The horizontal distance (range) $R$ is given by $R = u \times t$,where $u$ is the initial horizontal velocity.Given $R = 10 \, m$,we have $10 = u \times 1$.Therefore,$u = 10 \, m/s$.

Class 11 Physics 3-2.Motion in Plane Horizontal Projectile Motion

Medium

$A$ body is thrown horizontally from the top of a tower of height $5 \, m$. It touches the ground at a distance of $10 \, m$ from the foot of the tower. The initial velocity of the body is ......... $m/s$ $(g = 10 \, m/s^2)$.

A
$2.5$
B
$5$
C
$10$
D
$20$

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3-2.Motion in Plane

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Horizontal Projectile Motion

If a stone projected from the ground takes $4 \, s$ to reach the topmost point of its trajectory,then the time of flight is .......... $s$.

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$A$ projectile is thrown in the upward direction making an angle of $60^{\circ}$ with the horizontal direction with a velocity of $150\, ms^{-1}$. Then the time after which its inclination with the horizontal is $45^{\circ}$ is

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$A$ particle is projected with velocity $u$ at an angle $\alpha$ with the horizontal,and another particle is projected with the same velocity $u$ at an angle $\alpha$ with the vertical. What is the ratio of their times of flight?

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The equations of motion of a projectile are given by $x = 36t$ metre and $2y = 96t - 9.8t^2$ metre. The angle of projection is:

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$A$ body is thrown horizontally from the top of a tower of height $5 \, m$. It touches the ground at a distance of $10 \, m$ from the foot of the tower. The initial velocity of the body is ......... $m/s$ $(g = 10 \, m/s^2)$.

Similar Questions

If a stone projected from the ground takes $4 \, s$ to reach the topmost point of its trajectory,then the time of flight is .......... $s$.

For a projectile,if $\alpha$ is the angle of projection,$R$ is the range,$h$ is the maximum height,and $T$ is the time of flight,then:

$A$ projectile is thrown in the upward direction making an angle of $60^{\circ}$ with the horizontal direction with a velocity of $150\, ms^{-1}$. Then the time after which its inclination with the horizontal is $45^{\circ}$ is

$A$ particle is projected with velocity $u$ at an angle $\alpha$ with the horizontal,and another particle is projected with the same velocity $u$ at an angle $\alpha$ with the vertical. What is the ratio of their times of flight?

The equations of motion of a projectile are given by $x = 36t$ metre and $2y = 96t - 9.8t^2$ metre. The angle of projection is:

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