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(D) The radius of the circle is $r = 10 \ m$. The time period for one complete revolution is $T = 4 \ s$.The angular velocity of the body is $\omega =

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$10\sqrt{2}$

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(D) The radius of the circle is $r = 10 \ m$. The time period for one complete revolution is $T = 4 \ s$.The angular velocity of the body is $\omega = \frac{2\pi}{T} = \frac{2\pi}{4} = \frac{\pi}{2} \ rad/s$.At time $t = 3 \ s$,the angle covered by the body is $	heta = \omega t = (\frac{\pi}{2}) 	imes 3 = \frac{3\pi}{2} \ rad$.This corresponds to a position $270^{\circ}$ from the starting point. If the starting point is at $(r, 0)$,the position after $3 \ s$ is $(0, -r)$.The displacement vector is the straight-line distance between the starting point $(r, 0)$ and the final point $(0, -r)$.Displacement $d = \sqrt{(r - 0)^2 + (0 - (-r))^2} = \sqrt{r^2 + r^2} = r\sqrt{2}$.Substituting $r = 10 \ m$,we get $d = 10\sqrt{2} \ m$.

$A$ body is moving with constant speed in a circle of radius $10 \ m$. The body completes one revolution in $4 \ s$. At the end of the $3^{rd}$ second,the displacement of the body (in $m$) from its starting point is:

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