A body dropped from a height 1,m on a floor r | vedclass

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(C) Let $h = 1\,m = 100\,cm$ be the initial height and $h_1 = 25\,cm$ be the height after the first rebound.When a body is dropped from a height $h$,i

Vedclass · Accepted Answer

$\frac{1}{2}$

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(C) Let $h = 1\,m = 100\,cm$ be the initial height and $h_1 = 25\,cm$ be the height after the first rebound.When a body is dropped from a height $h$,its velocity just before hitting the floor is $u = \sqrt{2gh}$.After the rebound,if the body rises to a height $h_1$,its velocity just after the collision is $v = \sqrt{2gh_1}$.The coefficient of restitution $e$ is defined as the ratio of the velocity of separation to the velocity of approach.$e = \frac{v}{u} = \frac{\sqrt{2gh_1}}{\sqrt{2gh}} = \sqrt{\frac{h_1}{h}}$.Substituting the given values:$e = \sqrt{\frac{25\,cm}{100\,cm}} = \sqrt{\frac{1}{4}} = \frac{1}{2}$.

$A$ body dropped from a height $1\,m$ on a floor rises to a height $25\,cm$ after the first rebound. The coefficient of restitution is

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