A boat goes 48, km downstream in 20, h. It ta | vedclass

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(A) Let the speed of the boat in still water be $x\, km/h$ and the speed of the stream be $y\, km/h$.Downstream speed $= (x + y)\, km/h$.Upstream spee

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$2.2$

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(A) Let the speed of the boat in still water be $x\, km/h$ and the speed of the stream be $y\, km/h$.Downstream speed $= (x + y)\, km/h$.Upstream speed $= (x - y)\, km/h$.According to the problem,the boat covers $48\, km$ downstream in $20\, h$:$x + y = \frac{48}{20} = 2.4\, km/h$ $....(1)$It takes $4\, h$ more to cover the same distance upstream,so the time taken is $20 + 4 = 24\, h$:$x - y = \frac{48}{24} = 2\, km/h$ $....(2)$Adding equations $(1)$ and $(2)$:$(x + y) + (x - y) = 2.4 + 2$$2x = 4.4$$x = 2.2\, km/h$Thus,the speed of the boat in still water is $2.2\, km/h$.

$A$ boat goes $48\, km$ downstream in $20\, h$. It takes $4\, h$ more to cover the same distance against the stream. What is the speed of the boat in still water? (in $km/h$)

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