A block of mass 8, kg is at rest on a rough i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) When a body is at rest on an inclined plane,the net force acting on it is zero.Therefore,the net force exerted by the surface on the block must ba

Vedclass · Accepted Answer

$80$

Vedclass · Answer

(D) When a body is at rest on an inclined plane,the net force acting on it is zero.Therefore,the net force exerted by the surface on the block must balance the weight of the block $(mg)$ to keep it in equilibrium.The force exerted by the surface consists of two components: the normal force $(N)$ perpendicular to the surface and the static frictional force $(f_s)$ parallel to the surface.$N = mg \cos 	heta$$f_s = mg \sin 	heta$The magnitude of the net force $(F)$ exerted by the surface is given by:$F = \sqrt{N^2 + f_s^2} = \sqrt{(mg \cos 	heta)^2 + (mg \sin 	heta)^2}$$F = \sqrt{m^2g^2(\cos^2 	heta + \sin^2 	heta)} = mg$Given $m = 8\, kg$ and taking $g = 10\, m/s^2$:$F = 8 	imes 10 = 80\, N$.

$A$ block of mass $8\, kg$ is at rest on a rough inclined plane as shown in the figure. The magnitude of the net force exerted by the surface on the block will be ......... $N$.

Similar Questions

Which of the following is the order of maize?

Assertion : $LiCl$ is predominantly a covalent compound.
Reason : Electronegativity difference between $Li$ and $Cl$ is too small.

Lithium shows similarities to magnesium in its chemical behaviour because

The pair of straight lines is represented by the equation $3dx^2 - 5xy + (d^2 - 2)y^2 = 0$. If the lines are perpendicular to each other,for how many values of $d$ will this condition be satisfied?

If $\alpha, \beta, \gamma$ are the roots of $x^3-2x^2+3x-4=0$,then the value of $\alpha^2\beta^2+\beta^2\gamma^2+\gamma^2\alpha^2$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module