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Question

(B) The formula for the angle of deviation $\delta$ is given by $\delta = i + e - A$.For an equilateral prism,the angle of the prism $A = 60^{\circ}$.

Vedclass · Accepted Answer

$< 30^{\circ}$

Vedclass · Answer

(B) The formula for the angle of deviation $\delta$ is given by $\delta = i + e - A$.For an equilateral prism,the angle of the prism $A = 60^{\circ}$.Given $i = 50^{\circ}$ and $e = 40^{\circ}$,we calculate the deviation:$\delta = 50^{\circ} + 40^{\circ} - 60^{\circ} = 30^{\circ}$.The angle of minimum deviation $\delta_{m}$ occurs when $i = e$. Since the current deviation is $30^{\circ}$ at $i 
eq e$,the minimum deviation $\delta_{m}$ must be less than the deviation at any other angle of incidence.Therefore,$\delta_{m} < 30^{\circ}$.

$A$ beam of monochromatic light is incident at $i = 50^{\circ}$ on one face of an equilateral prism. If the angle of emergence is $e = 40^{\circ}$,then the angle of minimum deviation is:

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