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(D) The angle of incidence $i$ is the angle between the incident ray and the normal. From the diagram,the angle between the incident ray and the surfa

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The intensity gradually reduces to zero and then again increases.

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(D) The angle of incidence $i$ is the angle between the incident ray and the normal. From the diagram,the angle between the incident ray and the surface is $33^{\circ}$. Therefore,the angle of incidence $i = 90^{\circ} - 33^{\circ} = 57^{\circ}$.Given the refractive index $\mu = 1.54$ and $	an 57^{\circ} = 1.54$,we have $\mu = 	an i_p$,where $i_p$ is the Brewster's angle.Since the light is incident at Brewster's angle,the reflected ray $OB$ is completely plane-polarized.When this plane-polarized light passes through a rotating polaroid,the intensity $I$ of the transmitted light varies according to Malus's Law: $I = I_0 \cos^2 	heta$,where $	heta$ is the angle between the transmission axis of the polaroid and the plane of polarization of the light.As the polaroid is rotated,the intensity will gradually decrease to zero (when $	heta = 90^{\circ}$) and then increase again as the polaroid continues to rotate.

$A$ beam of light $AO$ is incident on a glass slab $(\mu = 1.54)$ in a direction as shown in the diagram. The reflected ray $OB$ is passed through a polaroid. On viewing through the polaroid,we find that on rotating the polaroid: (Given $\tan 57^{\circ} = 1.54$)

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