A battery of 3.0 V is connected to a resisto | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given:Electromotive force $E = 3.0 \ V$Terminal voltage $V = 2.5 \ V$Power dissipated by external resistor $P_R = 0.5 \ W$We know that the termina

Vedclass · Accepted Answer

$0.10$

Vedclass · Answer

(D) Given:Electromotive force $E = 3.0 \ V$Terminal voltage $V = 2.5 \ V$Power dissipated by external resistor $P_R = 0.5 \ W$We know that the terminal voltage $V$ is given by $V = E - ir$,where $i$ is the current and $r$ is the internal resistance.$2.5 = 3.0 - ir$$ir = 0.5 \ V$The power dissipated in the internal resistance is $P_r = i^2r = (ir) \cdot i$.Since $V = iR = 2.5 \ V$,we have $i = \frac{2.5}{R}$.Also,$P_R = i^2R = 0.5 \ W$.Substituting $i = \frac{2.5}{R}$ into $P_R = i^2R$:$0.5 = (\frac{2.5}{R})^2 \cdot R = \frac{6.25}{R}$$R = \frac{6.25}{0.5} = 12.5 \ \Omega$.Now,find the current $i$:$i = \frac{V}{R} = \frac{2.5}{12.5} = 0.2 \ A$.Finally,calculate the power dissipated in the internal resistance $P_r$:$P_r = i^2r = i(ir) = 0.2 \ A 	imes 0.5 \ V = 0.10 \ W$.

$A$ battery of $3.0 \ V$ is connected to a resistor dissipating $0.5 \ W$ of power. If the terminal voltage of the battery is $2.5 \ V$,the power dissipated within the internal resistance is $....... \ W$.

Similar Questions

In the circuit shown below,the power developed in the $6 \, \Omega$ resistor is $6 \, W$. The power in watts developed in the $4 \, \Omega$ resistor is

In the network shown in the figure,the potential difference across the $2R$ resistor is...... (The cell has an $emf$ $E$ and no internal resistance).

In how much time will one litre of ${H_2}$ be collected by a $5\, A$ current? (Given: $Z = 1 \times {10^{ - 8}}\,kg/C$ and density of ${H_2} = 0.09\,kg/{m^3}$)

$A$ $DC$ supply of $160 \ V$ is used to charge a battery of $EMF$ $10 \ V$ and internal resistance $1 \ \Omega$ by connecting a series resistance of $24 \ \Omega$. The terminal voltage of the battery during charging is (in $V$)

In the circuit shown in the figure,the potential difference between points $A$ and $B$ is $16\,V$. The current passing through the $2\,\Omega$ resistance will be $...........\,A$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module