$A$ bar of iron is $10 \, cm$ at $20^{\circ}C$. At $19^{\circ}C$ it will be ($\alpha$ of iron $= 11 \times 10^{-6}/^{\circ}C$)

  • A
    $11 \times 10^{-6} \, cm$ longer
  • B
    $11 \times 10^{-6} \, cm$ shorter
  • C
    $11 \times 10^{-5} \, cm$ shorter
  • D
    $11 \times 10^{-4} \, cm$ shorter

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