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(B) The initial velocity of the centre of mass $(V_{cm})$ is given by:$V_{cm} = \frac{m_1 v_1 + m_2 v_2}{m_1 + m_2} = \frac{1 	imes 4 + 2 	imes 0}{1

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The centre of mass first moves up and then comes down.

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(B) The initial velocity of the centre of mass $(V_{cm})$ is given by:$V_{cm} = \frac{m_1 v_1 + m_2 v_2}{m_1 + m_2} = \frac{1 	imes 4 + 2 	imes 0}{1 + 2} = \frac{4}{3}\, m/s$ (upwards).Since both balls are under the influence of gravity,the acceleration of each ball is $g$ downwards.The acceleration of the centre of mass $(a_{cm})$ is given by:$a_{cm} = \frac{m_1 a_1 + m_2 a_2}{m_1 + m_2} = \frac{1 	imes (-g) + 2 	imes (-g)}{1 + 2} = -g$ (downwards).Since the centre of mass has an initial upward velocity and a constant downward acceleration,it will first move up,reach a maximum height,and then come down.

$A$ ball of mass $1\, kg$ is thrown up with an initial speed of $4\, m/s$. $A$ second ball of mass $2\, kg$ is released from rest from some height as shown in the figure. Select the correct alternative.

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