(A) The total height $h$ of the tower is given by the equation of motion for a body falling from rest: $h = \frac{1}{2}gT^2$.At time $t = T/3$,the dis

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(A) The total height $h$ of the tower is given by the equation of motion for a body falling from rest: $h = \frac{1}{2}gT^2$.At time $t = T/3$,the distance $h'$ covered by the ball from the top is: $h' = \frac{1}{2}g(T/3)^2 = \frac{1}{2}g(T^2/9) = \frac{1}{9}(\frac{1}{2}gT^2) = \frac{h}{9}$.The position of the ball from the ground is the total height minus the distance covered from the top: $h_{ground} = h - h' = h - \frac{h}{9} = \frac{8h}{9}$ meters.

Class 11 Physics Motion in Straight Line Motion Under Gravity

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$A$ ball is released from the top of a tower of height $h$ meters. It takes $T$ seconds to reach the ground. What is the position of the ball at $T/3$ seconds?

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A
$8h/9$ meters from the ground
B
$7h/9$ meters from the ground
C
$h/9$ meters from the ground
D
$17h/18$ meters from the ground

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Motion in Straight Line

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Motion Under Gravity

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$A$ ball is released from the top of a tower of height $h$ meters. It takes $T$ seconds to reach the ground. What is the position of the ball at $T/3$ seconds?

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Draw graphs $a \to t$,$v \to t$,and $x \to t$ for an object falling freely.

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