A ball is dropped from the top of a tower of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let the first ball dropped from the top travel a distance $h_1$ in time $t$. Using the equation of motion $s = ut + \frac{1}{2}at^2$,where $u = 0$

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(B) Let the first ball dropped from the top travel a distance $h_1$ in time $t$. Using the equation of motion $s = ut + \frac{1}{2}at^2$,where $u = 0$ and $a = g$,we get:$h_1 = \frac{1}{2}gt^2$Let the second ball thrown from the bottom travel a distance $h_2$ in the same time $t$. Using $s = ut - \frac{1}{2}gt^2$,where $u = 50 \, m/s$,we get:$h_2 = 50t - \frac{1}{2}gt^2$Since the total height of the tower is $100 \, m$,the sum of the distances covered by both balls when they meet is equal to the height of the tower:$h_1 + h_2 = 100$Substituting the expressions for $h_1$ and $h_2$:$\frac{1}{2}gt^2 + (50t - \frac{1}{2}gt^2) = 100$$50t = 100$$t = 2 \, s$Thus,the balls will cross each other after $2 \, s$.

$A$ ball is dropped from the top of a tower of $100 \, m$ height. Simultaneously,another ball is thrown upward from the bottom of the tower with a speed of $50 \, m/s$ $(g = 10 \, m/s^2)$. They will cross each other after . . . . . . $s$.

Similar Questions

$A$ body starts to fall freely under gravity. The distances covered by it in the first,second,and third seconds are in the ratio:

$A$ body falls from a large height. The ratio of distance traveled in each time interval $t_0$ during $t = 0$ to $t = 3\, t_0$ of the journey is

Two bodies of masses $m_1$ and $m_2$ are dropped from two different heights $h_1$ and $h_2$ respectively. The ratio of the times taken by the two masses to touch the ground is (neglect air resistance)

Draw the graph of $y$ versus $t$ for an object falling freely,where $y$ is the vertical displacement and $t$ is time.

$A$ balloon is at a height of $81\, m$ and is ascending upwards with a velocity of $12\, m/s$. $A$ body of $2\, kg$ weight is dropped from it. If $g = 10\, m/s^2$,the body will reach the surface of the earth in ......... $s$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module