$A$ ball dropped from the top of a tower falls the first half of the height of the tower in $10 \, s$. The total time spent by the ball in the air is ......... $s$. [Take $g = 10 \, m/s^2$]

$A$ particle is thrown with any velocity vertically upward. The distance travelled by the particle in the first second of its descent is:

Galileo's law of odd numbers: "The distances traversed, during equal intervals of time, by a body falling from rest, stand to one another in the same ratio as the odd numbers beginning with unity [namely, $1: 3: 5: 7 \ldots$]". Prove it.

$A$ body is thrown vertically upwards. If air resistance is to be taken into account,then the time during which the body rises is

$A$ ball is thrown vertically downward with a velocity of $20\; m/s$ from the top of a tower. It hits the ground after some time with a velocity of $80\; m/s$. The height of the tower is $......m$ : $(g = 10\; m/s^2)$

$A$ body is projected upwards with a speed $u$ and the time taken by it to reach the maximum height $H$ is $T$. Pick out the correct statement.