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(C) The sample space $S$ for rolling a die is $\{1, 2, 3, 4, 5, 6\}$,so the total number of outcomes is $6$.The prime numbers between $1$ and $6$ are

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$\frac{1}{2}$

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(C) The sample space $S$ for rolling a die is $\{1, 2, 3, 4, 5, 6\}$,so the total number of outcomes is $6$.The prime numbers between $1$ and $6$ are $2, 3,$ and $5$.Thus,the number of favorable outcomes is $3$.The probability of getting a prime number is given by the ratio of the number of favorable outcomes to the total number of outcomes.Probability $= \frac{	ext{Number of favorable outcomes}}{	ext{Total number of outcomes}} = \frac{3}{6} = \frac{1}{2}$.

$A$ balanced die is rolled once. Then,the probability that the number on the die is a prime number is .........

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