A bag contains $4$ white and $3$ red balls. Two draws of one ball each are made without replacement. Then the probability that both the balls are red is
A bag contains $4$ white and $3$ red balls. Two draws of one ball each are made without replacement. Then the probability that both the balls are red is
- A
$\frac{1}{7}$
- B
$\frac{2}{7}$
- C
$\frac{3}{7}$
- D
$\frac{4}{7}$
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