A $100\, W$ bulb $B_1$, and two $60\,W$ bulbs $B_2$ and $B_3$, are connected to a $250\, V$ source, as shown in the figure. Now $ W_1, W_2$ and $W_3$ are the output powers of the bulbs $B_1, B_2$ and $B_3$, respectively. Then

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  • [IIT 2002]
  • A

    ${W_1} > {W_2} = {W_3}$

  • B

    ${W_1} > {W_2} > {W_3}$

  • C

    ${W_1} < {W_2} = {W_3}$

  • D

    ${W_1} < {W_2} < {W_3}$

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