A $5.0\, amp$ current is setup in an external circuit by a $6.0\, volt$ storage battery for $6.0$ minutes. The chemical energy of the battery is reduced by

  • A

    $1.08 \times 10^{4} \,J$

  • B

    $1.08 \times 10^{-4}\, Volt$

  • C

    $1.8 \times 10^{4} \,J$

  • D

    $1.08 \times 10^{4} \,Volt$

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$(2)$  The product of a volt and an ampere is a joule/second.

$(3)$  The product of volt and watt is horse power.

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