A 100, watt bulb working on 200 ,volt and a 2 | vedclass

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Question

(b) $R = \frac{{{V^2}}}{P}$ $ \Rightarrow $ ${R_1} = \frac{{200 	imes 200}}{{100}} = 400\,\Omega $ and
${R_2} = \frac{{100 	imes 100}}{{200}} = 50\

Vedclass · Accepted Answer

Maximum current ratings in the ratio of $1:4$

Vedclass · Answer

(b) $R = \frac{{{V^2}}}{P}$ $ \Rightarrow $ ${R_1} = \frac{{200 	imes 200}}{{100}} = 400\,\Omega $ and
${R_2} = \frac{{100 	imes 100}}{{200}} = 50\,\Omega .$ Maximum current rating $i = \frac{P}{V}$
So ${i_1} = \frac{{100}}{{200}}$ and ${i_2} = \frac{{200}}{{100}}$$ \Rightarrow $ $\frac{{{i_1}}}{{{i_2}}} = \frac{1}{4}$.

A $100\, watt$ bulb working on $200 \,volt$ and a $200\, watt$ bulb working on $100\, volt$ have

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